-4x^2=13x=14

Solution for -4x^2=13x=14 equation:

-4x^2=13x=14

We move all terms to the left:

-4x^2-(13x)=0

a = -4; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·(-4)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*-4}=\frac{0}{-8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*-4}=\frac{26}{-8}
=-3+1/4
$